Dosage
Lbs/Day gas - 1
FIRST. Read the question CAREFULLY and look for KEY WORDS to help you decide what formula to use.
You have to disinfect a trapezoid water basin with a dose of 4.8 mg/l that is 35 ft on top and 25 ft at the base, water level is at 15 feet. And the length is 50 feet. How many pounds a day of CL2 gas will you need?
SECOND. By using the KEY WORDS you see this is a (Dose) problem, that includes (Lbs/day).
The Formula (F) and Conversions & Calculations (C&C) shown below.
Trapezium, Ft2 = (Top + Base) x Height / Depth (C&C)1
2
Gallons = Ft2 x Ft/Length x 7.48 gal/ft3 (C&C)2
MGD = Gallons divided by 1,000,000 (C&C)3
Lbs/Day gas feed dry = MGD x ppm or mg/l x 8.34 lbs/gal (F)4
THIRD. Follow the solution procedure below to solve the problem!
(35 ft/top + 25 ft/base) x 15 ft = 900 ft = 450 ft2
2 2
450 ft2 x 50 ft x 7.48 gal/ft3 = 168,300 gal
168,300 gal / 1,000,000 = .1683 MGD
.1683 MGD x 4.8 mg/l x 8.34 lbs/gal = 6.74 lbs/gal
Lbs/Day - 1
FIRST. Read the question CAREFULLY and look for KEY WORDS to help you decide what formula to use.
You are using Soda Ash to treat 3.5 MGD of water, with a dosage of 6.5 mg/l, the lime is 85% purity. How many Pounds per day will you need?
SECOND. By using the KEY WORDS you see this is a (Dosage) problem, that includes (pounds per day).
The Formula (F) and Conversions & Calculations (C&C) shown below.
Decimal = % divided by 100 (C&C)1
Lbs/day = MGD x ppm or mg/l x 8.34 lbs/gal (F)2
% purity / 100
THIRD. Follow the solution procedure below to solve the problem!
85% / 100 = .85
3.5 MGD x 6.5 mg/l x 8.34 lbs/gal = 223.2 Lbs/day
.85
Lbs/Day - 2
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FIRST. Read the question CAREFULLY and look for KEY WORDS to help you decide what formula to use.
870 ft of 8” Ductile Iron water main was installed, you have to disinfect it with 70% strength calcium hypochlorite tablets HTH, with a dose of 25mg/l for 24 hours. How many lbs of calcium hypochlorite do you need?
SECOND. By using the KEY WORDS you see this is a (Chemical Dose) problem, that includes (lbs, % strength).
The Formula (F) and Conversions & Calculations (C&C) are shown below.
Dia/Ft = Dia/Inches divided by 12 In/Ft (C&C)1
Cyl, Gal = 0.785 x (Dia/ft)2 x Ht, Depth or Lgth x 7.48 gal/ft3 (C&C)2
MGD = Gallons divided by 1,000,000 (C&C)3
Decimal = % divided by 100 (C&C)4
Lbs/day = MGD x ppm or mg/l x 8.34 lbs/gal (F)5
% purity / 100
THIRD. Follow the solution procedure below to solve the problem!
8 dia/in / 12 in/ft = .667 dia/ft
.785 x .667 dia/ft x .667 dia/ft x 870 ft x 7.48 gal/ft3 = 2,272.7 gal
2,272.7 gal / 1,000,000 = .00227 MGD
70% / 100 = .70
.00227 MGD x 25 mg/l x 8.34 lbs/gal = .473 lbs = .68 lbs
.70 .70
Gal per Day - 1
FIRST. Read the question CAREFULLY and look for KEY WORDS to help you decide what formula to use.
A water treatment plant is treating 2.5 MGD of water. How many gallons per day of 7.5% Sodium hypochlorite will be needed for disinfection, the dosage required is 21 mg/l.
SECOND. By using the KEY WORDS you see this is a (Dosage) problem, that includes (GPD).
The Formula (F) and Conversions & Calculations (C&C) are shown below.
Decimal = % divided by 100 (C&C)1
GPD = MGD x ppm or mg/l x 8.34 lbs/gal (F)2
% purity / 100 x lbs/gal
THIRD. Follow the solution procedure below to solve the problem!
7.5% / 100 = .075
2.5 MGD x 21 mg/l x 8.34 lbs = 437.85 lbs = 700.56 GPD
.075 x 8.34 lbs .625 lbs
Gal per Day - 2
FIRST. Read the question CAREFULLY and look for KEY WORDS to help you decide what formula to use.
A water treatment plant is treating 3,000,000 gallons a day of water. How many gallons per day of 8.0% Sodium hypochlorite will be needed for disinfection, the dosage required is 19 mg/l.
SECOND. By using the KEY WORDS you see this is a (Dosage) problem, that includes (GPD).
The Formula (F) and Conversions & Calculations (C&C) are shown below.
MGD = Gallons divided by 1,000,000 (C&C)1
Decimal = % divided by 100 (C&C)2
GPD = MGD x ppm or mg/l x 8.34 lbs/gal (F)3
% purity / 100 x lbs/gal
THIRD. Follow the solution procedure below to solve the problem!
3,000,000 / 1,000,000 = 3 MGD
8.0% / 100 = .08
3 MGD x 19 mg/l x 8.34 lbs = 475.38 lbs = 1,140 GPD
.08 x 8.34 lbs .417 lbs
ppm or mg/l - 1
FIRST. Read the question CAREFULLY and look for KEY WORDS to help you decide what formula to use.
A treatment plant feeds 250 lbs a day of chlorine and treats 15.5 MGD. What if the dosage in mg/l?
SECOND. By using the KEY WORDS you see this is a (Dosage) problem, that includes (mg/l).
The Formula (F) and Conversions & Calculations (C&C) shown below.
ppm or mg/l = lbs/day (F)
MGD x 8.34 lbs/gal
THIRD. Follow the solution procedure below to solve the problem!
250 lb/d = 250 lb/d = 1.93 mg/l
15.5 MGD x 8.34 lbs/gal 129.27 lbs/MGD
ppm or mg/l - 2
FIRST. Read the question CAREFULLY and look for KEY WORDS to help you decide what formula to use.
A treatment plant is flowing water at 70,834 pallons per hour. You are dosing it 71 pounds of aluminum sufate par day. What is the dose in ppm?
SECOND. By using the KEY WORDS you see this is a (Dosage) problem, that includes (mg/l,ppm).
The Formula (F) and Conversions & Calculations (C&C) are shown below.
Gal/day = gal/hr x 24 hr/day (C&C)1
MGD = Gallons divided by 1,000,000 (C&C)2
ppm or mg/l = lbs/day (F)3
MGD x 8.34 lbs/gal
THIRD. Follow the solution procedure below to solve the problem!
70,834 gal/hr x 24 hr = 1,700,016 gal/day
1,700,016 / 1,000,000 = 1.7 MGD
71 lbs/day = 71 lbs/day = 5 ppm
1.7 MGD x 8.34 lbs 14.18 lbs
ppm or mg/l - 3
FIRST. Read the question CAREFULLY and look for KEY WORDS to help you decide what formula to use.
6,000 ft of 12” Ductile Iron water main was installed, you have to disinfect it with 7.5 pounds of calcium hypochlorite tablets HTH ( dry chlorine ). what is the dose in mg/l?
SECOND. By using the KEY WORDS you see this is a (Dosage) problem, that includes (mg/l,ppm).
The Formula (F) and Conversions & Calculations (C&C) are shown below.
Dia/Ft = Dia/Inches divided by 12 In/Ft (C&C)1
Cyl, Gal = 0.785 x (Dia/ft)2 x Ht, Dpth or Lgth x 7.48 gal/ft3 (C&C)2
MGD = Gallons divided by 1,000,000 (C&C)3
ppm or mg/l = lbs/day (F)4
MGD x 8.34 lbs/gal
THIRD. Follow the solution procedure below to solve the problem!
12 dia/in / 12 in/ft = 1 dia/ft
.785 x 1 dia/ft x 1 dia/ft x 6,000 ft x 7.48 gal/ft3 = 35,230.8 gal
35,230.8 gal / 1,000,000 = .035 MGD
7.5 lbs/day = 7.5 lbd/day = 25.7 ppm
.035 MGD x 8.34 lbs .292 lbs
ppm or mg/l % - 1
FIRST. Read the question CAREFULLY and look for KEY WORDS to help you decide what formula to use.
The flow in your treatment plant is 2 MG. The hypochlorinator injects at 3 gal/hr, with 7% chlorine. What is the dose in mg/l?
SECOND. By using the KEY WORDS you see this is a (Dosage) problem, that includes (mg/l,%).
The Formula (F) and Conversions & Calculations (C&C) shown below.
Gal/day = gal/hr x 24 hr/day (C&C)1
Decimal = % divided by 100 (C&C)2
ppm or mg/l % = Gal x % purity / 100 x lbs/gal (F)3
MG x 8.34 lbs/gal
THIRD. Follow the solution procedure below to solve the problem!
3 gal/hr x 24 hr/day = 72 gal/day
7% / 100 = .07
72 gal x .07 x 8.34 lbs/gal = 42 lbs = 2.52 mg/l
2 MG x 8.34 lbs/gal 16.68 lbs
ppm or mg/l % - 2
FIRST. Read the question CAREFULLY and look for KEY WORDS to help you decide what formula to use.
Your well site is pumping 1,500,000 gal. The hypochlorinator injects at .67 ft3/hr, with 9% chlorine. What is the dose in mg/l?
SECOND. By using the KEY WORDS you see this is a (Dosage) problem, that includes (mg/l,ppm,%).
The Formula (F) and Conversions & Calculations (C&C) are shown below.
Gallons = Ft3 x 7.48 gal/ft3 (C&C)1
Gal/day = gal/hr x 24 hr/day (C&C)2
Decimal = % divided by 100 (C&C)3
MG = Gallons divided by 1,000,000 (C&C)4
ppm or mg/l % = Gal x % purity / 100 x lbs/gal (F)5
MG x 8.34 lbs/gal
THIRD. Follow the solution procedure below to solve the problem!
.67 ft3 x 7.48 ft3/gal = 5 gal
5 gal x 24 hr/day = 120 gal/day
9% / 100 = .09
1,500,000 / 1,000,000 = 1.5 MG
120 gal x .09 x 8.34 lbs = 90.1 lbs = 7.2 mg/l
1.5 MG x 8.34 lbs 12.51 lbs