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Pressure

PSI - 1

 

FIRST. Read the question CAREFULLY and look for KEY WORDS to help you decide what formula to use.

 

The water level in a reservoir is at 25 feet. What is the Pressure at the bottom of the reservoir?

 

SECOND. By using the KEY WORDS you see this is a (Pressure) problem, that includes (PSI).

The Formula (F) and Conversions & Calculations (C&C) are shown below.

   

PSI = Head, ft (F)

         2.31 ft/PSI

 

THIRD. Follow the solution procedure below to solve the problem!

 

     25 ft.   =  10.8 PSI

2.31 ft/PSI

PSI - 2

FIRST. Read the question CAREFULLY and look for KEY WORDS to help you decide what formula to use.

 

What is the PSI in a water storage tank that is 50 feet tall? The PSI gauge is installed 10 feet above the bottom of the tank, and the overflow is 5 ft below the top. Assume that the tank is full.

 

SECOND. By using the KEY WORDS you see this is a (Pressure) problem, that includes (PSI).

The Formula (F) and Conversions & Calculations (C&C) are shown below.

 

Head, ft = Height / Depth, add or subtract variables (C&C)1

 

PSI = Head, ft (F)2

       2.31 ft/PSI

 

THIRD. Follow the solution procedure below to solve the problem!

 

50 ft/tall – 10 ft – 5 ft = 35 head, ft

 

35 head, ft = 15.15 PSI

2.31 ft/PSI

PSI - 3

FIRST. Read the question CAREFULLY and look for KEY WORDS to help you decide what formula to use.

 

You have been sent to a 5 story hotel to do a pressure check for them. The pressure at the groud floor is 75 PSI. what is the pressure at 20 feet and 50 feet?

 

The Formula (F) and Conversions & Calculations (C&C) are shown below.

SECOND. By using the KEY WORDS you see this is a (Pressure) problem, that includes (PSI).

       

PSI = Head, ft (F)1

      2.31 ft/PSI

 

PSI = PSI (Ground Floor) – PSI (20 ft, 50 ft) (C&C)2

 

THIRD. Follow the solution procedure below to solve the problem!

 

      20 ft   =  8.66 PSI

2.31 ft/PSI

75 PSI – 8.66 PSI = 66.34 PSI

     50 ft    =  21.65 PSI

2.31 ft/PSI

 

75 PSI – 21.65 PSI = 53.35 PSI

PSI - 4

FIRST. Read the question CAREFULLY and look for KEY WORDS to help you decide what formula to use.

 

A water tank measures 35 ft in diameter, and 60 ft tall. What is the PSI at the bottom of the tank, if the tank is full?

 

SECOND. By using the KEY WORDS you see this is a (Pressure) problem, that includes (psi, feet).

The Formula (F) and Conversions & Calculations (C&C) are shown below.

 

PSI = Head, ft (F)

      2.31 ft/PSI

 

THIRD. Follow the solution procedure below to solve the problem!

 

     60 ft    =  25.97 PSI

2.31 ft/psi

PSI - 5

FIRST. Read the question CAREFULLY and look for KEY WORDS to help you decide what formula to use.

 

What is the PSI at a restaurant that is 175 feet below a water tank that is 70 feet tall. The water overflow of the tank is 5 feet below the top, assume the tank is full.

 

SECOND. By using the KEY WORDS you see this is a (Pressure) problem, that includes (psi, feet).

The Formula (F) and Conversions & Calculations (C&C) are shown below.

 

Head, ft = Height / Depth, add or subtract variables (C&C)1

 

PSI = Head, ft (F)2

      2.31 ft/PSI

 

THIRD. Follow the solution procedure below to solve the problem!

 

70 ft - 5 ft = 65 ft

 

175 ft + 65 ft = 240 ft

 

    240 ft   =   103.90 PSI

2.31 ft/PSI

PSI - 6

FIRST. Read the question CAREFULLY and look for KEY WORDS to help you decide what formula to use.

 

A water storage tank is 40 ft in diameter and has 234,872 gallons of water in it. What is the pressure at the bottom of the tank?

 

SECOND. By using the KEY WORDS you see this is a (Pressure) problem, that includes (psi, ft).

The Formula (F) and Conversions & Calculations (C&C) are shown below.

 

Head, ft = Gal (C&C)1

7.48 gal/ft3 x .785 x (dia,ft)2

 

PSI = Head, ft (F)2

      2.31 ft/PSI

 

THIRD. Follow the solution procedure below to solve the problem!

 

                 234,872 gal          =       234,872 gal  =  25 ft

7.48 gal x .785 x 40 ft x 40 ft       9,394.88 gal

 

     25 ft     =  10.82 PSI

2.31 ft/PSI

Head, ft  - 1

FIRST. Read the question CAREFULLY and look for KEY WORDS to help you decide what formula to use.

 

The pressure at the bottom of a lake is 22 PSI. how deep is the lake?

 

The Formula (F) and Conversions & Calculations (C&C) are shown below.

SECOND. By using the KEY WORDS you see this is a (Pressure) problem, that includes (depth, ft).

 

Head, ft. = PSI x 2.31 ft/PSI (F)

 

THIRD. Follow the solution procedure below to solve the problem!

 

22 PSI x 2.31 ft/PSI = 50.82 ft.

Head, ft - 2

FIRST. Read the question CAREFULLY and look for KEY WORDS to help you decide what formula to use.

 

You have a water main running up a hill, the first half is 6 inch and the second half is bushed down to 4 inch. The pressure at the bottom of the hill is 50 PSI. How long is the pipe?

 

SECOND. By using the KEY WORDS you see this is a (Pressure) problem, that includes (head, ft).

The Formula (F) and Conversions & Calculations (C&C) are shown below.

 

Head, ft = PSI x 2.31 ft/PSI (F)

 

THIRD. Follow the solution procedure below to solve the problem!

 

50 PSI x 2.31 ft/PSI = 115.5 Head, ft.

Head, ft - 3

FIRST. Read the question CAREFULLY and look for KEY WORDS to help you decide what formula to use.

 

A reservoir is 25 ft tall and 40 ft in dia, the gauge at the bottom the tank says 6.50 PSI. what is the height of water in the reservoir?

 

SECOND. By using the KEY WORDS you see this is a (Pressure) problem, that includes (height).

The Formula (F) and Conversions & Calculations (C&C) are shown below.

 

Head, ft = PSI x 2.31 ft/PSI (F)

 

THIRD. Follow the solution procedure below to solve the problem!

 

6.50 PSI x 2.31 ft/PSI = 15 ft

Head, ft - part 1

FIRST. Read the question CAREFULLY and look for KEY WORDS to help you decide what formula to use.

 

How many feet of water is in a water storage tank if the pressure gauge read is 15?

 

SECOND. By using the KEY WORDS you see this is a (Pressure) problem, that includes (ft,head).

The Formula (F) and Conversions & Calculations (C&C) are shown below.

 

Head, ft = PSI x 2.31 ft/PSI (F)

 

THIRD. Follow the solution procedure below to solve the problem!

 

15 PSI x 2.31 ft/PSI = 34.65 ft/head

Head, ft - part 2

FIRST. Read the question CAREFULLY and look for KEY WORDS to help you decide what formula to use.

 

How many feet of water is in a water storage tank if the pressure gauge read is 15?

The pressure gauge sits 10 feet below the the bottom of the tank.

 

SECOND. By using the KEY WORDS you see this is a (Pressure) problem, that includes (ft,head).

The Formula (F) and Conversions & Calculations (C&C) are shown below.

 

Head, ft = PSI x 2.31 ft/PSI (F)1

 

Head, ft = Height / Depth, add or subtract variables (C&C)2

 

THIRD. Follow the solution procedure below to solve the problem!

 

15 PSI x 2.31 ft/PSI = 34.65 ft,head

 

34.65 ft,head – 10 feet = 24.65 feet

Head, ft - part 3

FIRST. Read the question CAREFULLY and look for KEY WORDS to help you decide what formula to use.

 

How many feet of water is in a water storage tank if the pressure gauge read is 15?

The pressure gauge sits 10 feet above the the bottom of the tank.

 

SECOND. By using the KEY WORDS you see this is a (Pressure) problem, that includes (ft,head).

The Formula (F) and Conversions & Calculations (C&C) are shown below.

 

Head, ft = PSI x 2.31 ft/PSI (F)1

 

Head, ft = Height / Depth, add or subtract variables (C&C)2

 

THIRD. Follow the solution procedure below to solve the problem!

 

15 PSI x 2.31 ft/PSI = 34.65 ft,head

 

34.65 ft,head + 10 feet = 44.65 feet

Lbs Force - 1

FIRST. Read the question CAREFULLY and look for KEY WORDS to help you decide what formula to use.

 

A water tank in your system is 30 ft in dia, what is the total force in pounds at the bottom of the tank?

 

SECOND. By using the KEY WORDS you see this is a (Pressure) problem, that includes (pounds and force).

The Formula (F) and Conversions & Calculations (C&C) are shown below.

 

Lbs Force = 0.785 x Dia, ft2 x 144 in2/ft2PSI (F)

 

THIRD. Follow the solution procedure below to solve the problem!

 

.785 x 30 dia/ft x 30 dia/ft x 144 ins/ft2 PSI = 101,736 lbs force

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