Solutions
Lbs/gal - 1
FIRST. Read the question CAREFULLY and look for KEY WORDS to help you decide what formula to use.
What is the lbs per gallon of liquid chlorine if it’s 12% solution and the specific gravity is 1.41?
SECOND. By using the KEY WORDS you see this is a (Solution) problem, that includes (pounds per gallon, lbs/gal).
The Formula (F) and Conversions & Calculations (C&C) are shown below.
Decimal = % divided by 100 (C&C)1
Lbs/Gal = Solution% / 100 x 8.34 lbs/gal x Specific Gravity (F)2
THIRD. Follow the solution procedure below to solve the problem!
12% / 100 = .12
.12 x 8.34 lbs/gal x 1.41 sg = 1.41 lbs/gal
Lbs/gal - 2
FIRST. Read the question CAREFULLY and look for KEY WORDS to help you decide what formula to use.
What is the lbs per gallon of dry chlorine if it’s 65% solution and the specific gravity is 1.21?
SECOND. By using the KEY WORDS you see this is a (Solutions) problem, that includes (pounds per gallon).
The Formula (F) and Conversions & Calculations (C&C) are shown below.
Decimal = % divided by 100 (C&C)1
Lbs/Gal = Solution% / 100 x 8.34 lbs/gal x Specific Gravity (F)2
THIRD. Follow the solution procedure below to solve the problem!
65% / 100 = .65
.65 x 8.34 lbs/gal x 1.21 sg = 6.56 lbs/gal
Lbs/gal - 3
FIRST. Read the question CAREFULLY and look for KEY WORDS to help you decide what formula to use.
What is the lbs per gallon of Aluminum Sulfate if it has 30% solution and the specific gravity is 1.16?
SECOND. By using the KEY WORDS you see this is a (Solutions) problem, that includes (pounds per gallon).
The Formula (F) and Conversions & Calculations (C&C) are shown below.
Decimal = % divided by 100 (C&C)1
Lbs/Gal = Solution% / 100 x 8.34 lbs/gal x Specific Gravity (F)2
THIRD. Follow the solution procedure below to solve the problem!
30% / 100 = .30
.30 x 8.34 lbs/gal x 1.16 = 2.90 lbs/gal
Lbs Chemical - 1
FIRST. Read the question CAREFULLY and look for KEY WORDS to help you decide what formula to use.
The Specific Gravity of CL2 gas is 2.48, what is the chemical pounds in one gallon of water?
SECOND. By using the KEY WORDS you see this is a (Solutions) problem, that includes (lbs chemical).
The Formula (F) and Conversions & Calculations (C&C) shown below.
Lbs Chemical = Specific Gravity x 8.34 lbs/gal x solution,gal (F)
THIRD. Follow the solution procedure below to solve the problem!
2.48 CL2 x 8.34 lbs/gal x 1 gal = 20.68 Lbs
Specific Gravity - 1
FIRST. Read the question CAREFULLY and look for KEY WORDS to help you decide what formula to use.
The chemical weight of the solution in your treatment plant is 10.5 lbs/gal. What is the specific gravity?
SECOND. By using the KEY WORDS you see this is a (Solutions) problem, that includes (specific gravity).
The Formula (F) and Conversions & Calculations (C&C) shown below.
Specific Gravity = Chemical Wt. lbs/gal (F)
8.34 lbs/gal
THIRD. Follow the solution procedure below to solve the problem!
10.5 lbs/gal = 1.26 Specific Gravity
8.34 lbs/gal
Specific Gravity - 2
FIRST. Read the question CAREFULLY and look for KEY WORDS to help you decide what formula to use.
The chemical weight of the Alum solution in your treatment plant is 9.67 lbs/gal. What is the specific gravity?
SECOND. By using the KEY WORDS you see this is a (Solution) problem, that includes (specific gravity).
The Formula (F) and Conversions & Calculations (C&C) are shown below.
Specific Gravity = Chemical Wt. lbs/gal (F)
8.34 lbs/gal
THIRD. Follow the solution procedure below to solve the problem!
9.67 lbs/gal = 1.16 specific gravity
8.34 lbs/gal
Chemical Weight - 1
FIRST. Read the question CAREFULLY and look for KEY WORDS to help you decide what formula to use.
If the specific gravity of Sodium Hypochlorite is 1.41, what is the chemical weight?
SECOND. By using the KEY WORDS you see this is a (Solutions) problem, that includes (chemical weight).
The Formula (F) and Conversions & Calculations (C&C) are shown below.
Chemical Weight (lbs/gal) = Specific Gravity x 8.34 lbs/gal (F)
THIRD. Follow the solution procedure below to solve the problem!
1.41 x 8.34 lbs/gal = 11.76 lbs/gal
Chemical Weight - 2
FIRST. Read the question CAREFULLY and look for KEY WORDS to help you decide what formula to use.
If the specific gravity of Calcium Hypochlorite is 1.21, what is the chemical weight?
SECOND. By using the KEY WORDS you see this is a (Solutions) problem, that includes (chemical weight).
The Formula (F) and Conversions & Calculations (C&C) are shown below.
Chemical Weight (lbs/gal) = Specific Gravity x 8.34 lbs/gal (F)
THIRD. Follow the solution procedure below to solve the problem!
1.21 x 8.34 lbs/gal = 10.1 lbs/gal
GPD - 1
FIRST. Read the question CAREFULLY and look for KEY WORDS to help you decide what formula to use.
A water treatment plant flows 0.5 MGD, the water is treated with a dosage of 25 ppm at 30% strength. how may gallons per day is treated? The chemical weight is 11.25 lbs/gal
SECOND. By using the KEY WORDS you see this is a (Solutions) problem, that includes (gallons per day).
The Formula (F) and Conversions & Calculations (C&C) shown below.
Decimal = % divided by 100 (C&C)1
GPD = MGD x ppm or mg/l x 8.34 lbs/gal (F)2
% purity x chemical Wt. lbs/gal
THIRD. Follow the solution procedure below to solve the problem!
30% / 100 = .30
0.5 MGD x 25 ppm x 8.34 lbs/gal = 104.25 lbs/gal = 30.88 GPD
.30 x 11.25 lbs/gal 3.375 lbs/gal
GPD - 2
FIRST. Read the question CAREFULLY and look for KEY WORDS to help you decide what formula to use.
What is the solution mix in gallons per day (GPD) for a water treatment plant that is flowing 1,389 gal/min into a tank with a chlorine residual of .8 ppm and a demand of 1.2 ppm the strength is 23%
SECOND. By using the KEY WORDS you see this is a (Solutions) problem, that includes (GPD).
The Formula (F) and Conversions & Calculations (C&C) are shown below.
Gal/Day = Gal/min x 1,440 min/day (C&C)1
MGD = Gallons divided by 1,000,000 (C&C)2
Dose, ppm or mg/l = Demand + Residual (C&C)3
Decimal = % divided by 100 (C&C)4
GPD = MGD x ppm or mg/l x 8.34 lbs/gal (F)5
% purity x chemical Wt. lbs/gal
THIRD. Follow the solution procedure below to solve the problem!
1,389 gal/min x 1,440 min/day = 2,000,160 gal/day
2,000,160 / 1,000,000 = 2.0 MGD
1.2 ppm + .8 ppm = 2 ppm
23% / 100 = .23
2.0 MGD x 2 ppm x 8.34 lbs/gal = 33.4 lbs/day = 17.40 GPD
.23 x 8.34 lbs/gal 1.92 lbs